a) \(2^x\cdot4=128\)

\(\Rightarrow2^x\cdot2^2=2^7\)

\(\Rightarrow2^{x+2}=2^7\)

\(\Rightarrow x+2=7\)

\(\Rightarrow x=5\)

b) \(\left(2x+1\right)^3=125\)

\(\Rightarrow\left(2x+1\right)^3=5^3\)

\(\Rightarrow2x+1=5\)

\(\Rightarrow2x=4\)

\(\Rightarrow x=4:2\)

\(\Rightarrow x=2\)

c) \(2x-2^6=6\)

\(\Rightarrow2x-64=6\)

\(\Rightarrow2x=70\)

\(\Rightarrow x=70:2\)

\(\Rightarrow x=35\)

d) \(64\cdot4^x=45\)

\(\Rightarrow4^3\cdot4^x=45\)

\(\Rightarrow4^{x+3}=45\)

Xem lại đề

e) \(27\cdot3^x=243\)

\(\Rightarrow3^3\cdot3^x=3^5\)

\(\Rightarrow3^{x+3}=3^5\)

\(\Rightarrow x+3=5\)

\(\Rightarrow x=2\)

g) \(49\cdot7^x=2401\)

\(\Rightarrow7^2\cdot7^x=7^4\)

\(\Rightarrow7^{x+2}=7^4\)

\(\Rightarrow x+2=4\)

\(\Rightarrow x=2\)

h) \(3^x=81\)

\(\Rightarrow3^x=3^4\)

\(\Rightarrow x=4\)

k) \(3^4\cdot3^x=3^7\)

\(\Rightarrow3^{x+4}=3^7\)

\(\Rightarrow x+4=7\)

\(\Rightarrow x=3\)

n) \(3^x+25=26\cdot2^2+2\cdot3^0\)

\(\Rightarrow3^x+25=104+2\)

\(\Rightarrow3^x+25=106\)

\(\Rightarrow3^x=81\)

\(\Rightarrow3^x=3^4\)

\(x=4\)

`@` `\text {Ans}`

`\downarrow`

`a)`

`2^x*4 = 128`

`=> 2^x = 128 \div 4`

`=> 2^x = 2^7 \div 2^2`

`=> 2^x = 2^5`

`=> x = 5`

Vậy, `x = 5.`

`b)`

\(\left(2x+1\right)^3=125\)

`=> (2x + 1)^3 = 5^3`

`=> 2x + 1 = 5`

`=> 2x = 5-1`

`=> 2x = 4`

`=> x = 4 \div 2`

`=> x = 2`

Vậy, `x = 2`

`c)`

\(2x-2^6=6\)

`=> 2x = 6+2^6`

`=> 2x = 70`

`=> x = 70 \div 2`

`=> x = 35`

Vậy, `x = 35`

`d)`

\(64\cdot4^x=45\) Bạn xem lại đề

`e)`

`27*3^x = 243`

`=> 3^3 * 3^x = 3^5`

`=> 3^(3 + x) = 3^5`

`=> 3 + x = 5`

`=> x = 5 - 3`

`=> x = 2`

Vậy, `x = 2`

`g)`

`49* 7^x = 2401`

`=> 7^2 * 7^x = 7^4`

`=> 7^(2 + x) = 7^4`

`=> 2 + x = 4`

`=> x = 4 - 2`

`=> x = 2`

Vậy, `x = 2`

`h)`

`3^x = 81`

`=> 3^x = 3^4`

`=> x = 4`

Vậy, `x = 4`

`k)`

`3^4 * 3^x = 3^7`

`=> 3^(4 + x) = 3^7`

`=> 4 + x = 7`

`=> x = 7 - 4`

`=> x = 3`

Vậy, `x = 3`

`n)`

`3^x + 25 = 26*2^2 + 2*3^0`

`=> 3^x + 25 = 104 + 2`

`=> 3^x + 25 = 106`

`=> 3^x = 106 - 25`

`=> 3^x = 81`

`=> 3^x = 3^4`

`=> x = 4`

Vậy, `x = 4.`

\(#48Cd\)

a,  2 x . 2 2 = 32

2 x + 2 = 2 5

x + 2 = 5

x = 3

Vậy x = 3

b,  27 . 3 x = 243

3 3 . 3 x = 3 5

3 3 + x = 3 5

x + 3 = 5

x = 2

Vậy x = 2

c,  2 x . 2 4 = 1024

2 x + 4 = 2 10

x + 4 = 10

x = 6

Vậy x = 6

d,  49 . 7 x = 2401

7 2 . 7 x = 7 4

7 2 + x = 7 4

2 + x = 4

x = 2

Vậy x = 2

a)\(2x.4=128\)                                       

   \(2x=128:4\)                                                                                                 

  \(2x=32\)                                                        

    \(x=32:2\)

    \(x=16\)

Đề bạn hơi rối , mình dịch đề sai thì thông cảm ạ !

a) 2x . 4 = 128

=> 8x = 128

=> x = 16

b) ( 2x + 1 )³ = 125

=> ( 2x + 1 )³ = 5³

=> 2x + 1 = 5

=> 2x = 4

=> x = 2

c) Sửa đề : ( 2x - 2 ) . 6 = 6

=> 2x - 2 = 1

=> 2x = 3

=> x = 1,5

d) 64 . 4x = 45

=> 256x = 15

=> \(x=\frac{15}{256}\)

e) 27 . 3x = 243

=> 81x = 243

=> x = 3

f) 49 . 7x = 2401 

=> 343x = 2401

=> x = 7

g) 3x = 81

=> x = 81 : 3 = 27

h) 3⁴ . 3^x = 3⁷

=> 3^4+x = 3⁷

=> x + 4 = 7

=> x = 3

k) 3x + 2⁵ = 2⁶ . 2 + 2 . 3⁰

=> 3x + 2⁵ = 2⁷ + 2

=> 3x - 2 = 2⁷ - 2⁵

=> 3x - 2 = 2⁵ . ( 2² - 1 )

=> 3x - 2 = 32 . 3

=> 3x - 2 = 96

=> 3x = 98

Câu nài tui ko biết

3:

a: 3^x*3=243

=>3^x=81

=>x=4

b; 2^x*16^2=1024

=>2^x=4

=>x=2

c: 64*4^x=16^8

=>4^x=4^16/4^3=4^13

=>x=13

d: 2^x=16

=>2^x=2^4

=>x=4

a) \(\left(2x+1\right)^3=125\)

\(\left(2x+1\right)^3=5^3\)

\(2x+1=5\)

\(2x=4\)

\(x=2\)

b) \(3^x+25=26\times2^2+2\times3^0\)

\(3^x+25=26\times4+2\times1\)

\(3^x+25=106\)

\(3^x=106-25\)

\(3^x=81\)

\(3^x=3^4\)

\(x=4\)

(2x+1)3 = 125 

a)<=> (2x+1)3 = 53

<=> 2x+1 = 5

<=> 2x = 4

<=> x = 2

3^x+25=26 . 2^2 + 2. 3^0

b)3^x+25=104 +2

3^x+25=106

3^x=106+25

3^x=81=3^4

=> x=4                                                                      

a: Ta có: \(2^{x-1}=32\)

\(\Leftrightarrow x-1=5\)

hay x=6

b: Ta có: \(3^{2x+1}=81\)

\(\Leftrightarrow2x+1=4\)

\(\Leftrightarrow2x=3\)

hay \(x=\dfrac{3}{2}\)

c: Ta có: \(2^x-26=6\)

\(\Leftrightarrow2^x=32\)

hay x=5

d: Ta có: \(27\cdot3^x=243\)

\(\Leftrightarrow3^x=9\)

hay x=2

a) 245 - x = 27             b) 3x + 41 = 56        c) 238: 2x = 17      d) 3x - 90 = 24       e) 2x:5 = 124        h) 26 + 3x = 25 + 46 

             x = 245 - 27        3x = 56 -41              2x = 238: 17           3x = 24 + 90          2x = 124.5                6 + 3x = 71 

             x = 218                3x = 15                    2x = 14                  3x = 114                  2x = 620                  3x = 71 - 6

                                         x = 15 : 3                 x = 14: 2                 x = 114: 3               x = 620:2                  3x = 65

                                         x = 5                        x = 7                       x = 38                     x = 310                     x = 65: 3 

                                                                                                                                                                        x = 21,66 

\(a,245-x=27\)

\(x=245-27\)

\(x=218\)

\(b,3x+41=56\)

\(3x=56-41\)

\(3x=15\)

\(x=15:3\)

\(x=5\)

\(c,238:2x=17\)

\(2x=238:17\)

\(2x=14\)

\(x=14:2\)

\(x=7\)

\(d,3x-90=24\)

\(3x=24+90\)

\(3x=114\)

\(x=114:3\)

\(x=38\)

\(e,2x:5=124\)

\(2x=124\times5\)

\(2x=620\)

\(x=620:2\)

\(x=310\)

\(f,7x+4x=110\)

\(\left(7+4\right)x=110\)

\(11x=110\)

\(x=110:11\)

\(x=10\)

\(g,5x-x=444\)

\(\left(5-1\right)x=444\)

\(4x=444\)

\(x=444:4\)

\(x=111\)

\(h,26+3x=25+46\)

\(26+3x=71\)

\(3x=71-26\)

\(3x=45\)

\(x=45:3\)

\(x=15\)

Học tốt

CẢM ƠN NHA !